2x^2*32=78

Solution for 2x^2*32=78 equation:

2x^2*32=78

We move all terms to the left:

2x^2*32-(78)=0

Wy multiply elements

64x^2-78=0

a = 64; b = 0; c = -78;
Δ = b2-4ac
Δ = 02-4·64·(-78)
Δ = 19968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19968}=\sqrt{256*78}=\sqrt{256}*\sqrt{78}=16\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{78}}{2*64}=\frac{0-16\sqrt{78}}{128}
=-\frac{16\sqrt{78}}{128}
=-\frac{\sqrt{78}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{78}}{2*64}=\frac{0+16\sqrt{78}}{128}
=\frac{16\sqrt{78}}{128}
=\frac{\sqrt{78}}{8}
$